Sulphates : Gypsum (CaSO 4.2H 2O), Epsom salt (MgSO 4.7H 2O), Baryte (BaSO 4). Sulphates and sulphides are important sources of sulphur. On heating, H 3PO 3 disproportionates to give orthophosphoric acid and phosphine. H 3PO 4 contains three P-OH bonds and therefore, its basicity is three. Write a balanced equation for the hydrolytic reaction of PCl 5 in heavy water. Since axial bonds are weaker than equatorial bonds, therefore, when PCl 5 is heated, the less stable axial bond breaks to form PCl 3.
PCl 5 has three equatorial and two axial bonds. NaOH solution in an inert atmosphere of CO 2, phosphine gas is prepared. When white phosphorus is heated with cone. What happens when white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO 2 ? Hence, bond angle in PH 4 + ion is higher. PH 4 + is a regular tetrahedral structure, thus bond angle is 109☂8′. Therefore, the covalency of N in N 2O 5 is 4.īond angle in PH 4 + is higher than that in PH 3. Now in N 2O 5, each nitrogen atom has four shared pairs of electrons as shown : What is the covalence of nitrogen in N 2O 5 ?Ĭovalency depends upon the number of shared pairs of,electrons. How does ammonia reacts with a solution of Cu 2+?Īmmonia reacts with a solution of Cu +2 ions of solution to form deep blue coloured complex, tetra’amine copper (II) ion. Sometimes, Mo is also used as a promoter to increase the efficiency of the Fe catalyst.
To increase the rate of the reaction, a temperature of around 700 K is used and iron oxide mixed with some K 2O and Al 2O 3 is used as a catalyst. In accordance with Le-chatelier’s principle, to maximize the yield, a high pressure 200 atm is used. Mention the conditions required to maximise the yield of ammonia.Īmmonia is prepared by the Haber’s process. As a consequence, the bond dissociation energy of N 2 is very high and N 2 is less reactive at room temperature. In N 2 molecule, there is a strong pπ-pπ overlap that results in the formation of triple bond between N atoms (N ≡ N). Why is N 2 less reactive at room temperature? Therefore, it can readily lost H atom and has strongest tendency to act as reducing agent. Why is BiH 3 the strongest reducing agent amongst all the hydrides of Group 15 elements ?Īmong the hydrides of Group-15, BiH 3 is the least stable because Bi has largest size in group and has least tendency to form covalent bond with small hydrogen atom.
Hence pentahalides are more covalent than trihalide. Higher the positive oxidation state of central atom, it will have more polarising power which, in turn will increase the covalent character of the bond formed between the central atom and the other atom. Why are.pentahalides more covalent than trihalides ? MP Board Class 12th Chemistry Solutions Chapter 7 The p-Block Elements The p-Block Elements NCERT Intext Exercises
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